bullet of mass 40gm is fired from a gun of mass 8kg with a velocity of 800 m/s, calculate the recoil velocity of gun
(a) 1m/s
(b) -1m/s
(c) 2m/s
(d) -4m/s
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Question:-
bullet of mass 40gm is fired from a gun of mass 8kg with a velocity of 800 m/s, calculate the recoil velocity of gun
(a) 1m/s
(b) -1m/s
(c) 2m/s
(d) -4m/s
Given :
Mass of the bullet,M = 40gm= 0.04kg
Mass of the gun,m = 8kg
Velocity of bullet,u = 800ms⁻¹
To find :
The recoil of the gun(V)
Solution :
Initially both bullet and gun are at rest
⇒Intial momentum before firing = 0
______________________________
As no external force acts on the system
So According to the law of conservation of Momentum .
Total momentum before firing = Total momentum after the firing
⇒0 = mu+ Mv
⇒MV= -mu
⇒8× V= -0.04×800
Therefore;
⇒The negative sign shows that V and u are in opposite directions i.e ,the gun gives a kick in the backward direction or gun recoils with velocity v.
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