Question

bullet travels with a velocity 16 metre per second Pan track and come to rest in 0.4 m. find the time taken during the retardation​

Answer 1

$\huge\bf{ \underline{Question}}$

• A bullet travels with a velocity 16m/s and come to rest in 0.4m find the time taken during the retardation.

$\huge\bf{ \underline{Answer}}$

• 40 $\sf{m/\ s^{2}}$

$\huge\bf{ \underline{Formula\:Used}}$

$\sf{ \boxed{ \boxed{a\:=\:\dfrac{Velocity}{Time}}}}$

$\huge\bf{ \underline{Explanation}}$

${}$

$\mapsto\sf{Acceleration\:=\:\dfrac{Velocity}{Time}}$

${}$

$\mapsto\sf{Acceleration\:=\:\dfrac{16}{0.4}}$

${}$

$\mapsto\sf{Acceleration\:=\:\dfrac{160}{4}}$

${}$

$\mapsto\sf{Acceleration\:=\:\dfrac{\cancel{160}}{\cancel{4}}}$

${}$

$\mapsto\sf{Acceleration\:=\:40m/\ s^{2}}$

${}$

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1.

Retardation = - Acceleration

2.

Acceleration is vector quantity

3.

It's unit is $\sf{m/\ s^{2}}$

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Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

• bullet travels with a velocity 16 metre per second Pan track and come to rest in 0.4m find the time taken during the retardation

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Solution}}}}}}}}$

$\sf{\bold{\orange{\underline{\underline{Given}}}}}$

• intial velocity = u = 16m/sec
• final velocity = v = 0m/sec
• distance = 0.4meter

$\sf{\bold{\orange{\underline{\underline{To\:find}}}}}$

• time = ????

$\sf{\bold{\orange{\underline{\underline{Explanation}}}}}$

• using 3rd equation of motion

$\sf{\bold{\red{\boxed{\boxed{v^2-u^2 = 2as}}}}}$

$\sf 0 - 16^2 = 2 \times a \times 0.4$

$\sf - 256 = 0.8a$

$\sf a = \dfrac{-256}{0.8}$

$\sf a = - 320 meter/sec^2$

$\sf{\bold{\red{\boxed{\boxed{ retardiction = - accelaration }}}}}$

r = - (-320)meter/sec^2

r = 320 meter/sec^2

• using 1st eq of motion

$\sf{\bold{\red{\boxed{\boxed{v = u - at }}}}}$

0 = 16 - 320 t

0 - 16 = - 320 t

t = 16/ 320

t = 0.05 sec

$\sf{\bold{\pink{\boxed{\boxed{Time = 0.05 second}}}}}$

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