Question

Bullets of 0.03 kg mass each hit a plate at the
rate of 200 bullets per second, with a velocity of
50 m/s and reflect back with a velocity of 30 m
s. Find the average force acting on the plate.
​

Answer 1

Answer:

120 N

Explanation:

Time Taken,t=1 sec

Weight of bullet = 0.03kg

bullet fired per second=200

velocity of bullet fired=50m/s

rebound velocity of bullet=30m/s

Acc. to question

Change in momentum = impulse

Impulse=F×t

nMu-nMV=F×t

(n=200,M=0.03,V=30,u=50)

nM(u-V)=F×1

200×0.03(50-30)=F

6×20=F

120N=F