Math, asked by manikantareddymaram0, 1 month ago

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If the parallel sides of a trapezium are 22 cm and 38 cm, and its area is 585 cm?
find the height of the trapezium.​

Answers

Answered by OyeeKanak
77

Question:-

  • If the parallel sides of a trapezium are 22 cm and 38 cm, and its area is 585 cm? find the height of the trapezium.

Given:-

  • Heights of trapezium are 22cm and 38 cm

  • Area of trapezium is 585 cm²

To find:-

  • Height of trapezium

Solution:-

  • We know that area of trapezium is = ½×(a+b)+h

 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \implies \:  \frac{1}{2}  \times (22 + 38) \times h = 585 {cm}^{2}

 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \implies \:  \frac{1}{2}  \times 60 \times h = 585 {cm}^{2}

  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \implies \:  \frac{1}{ \cancel2}  \times  \cancel{836}  \:  \:  \: ^{30}  \times h = 585

 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  : \implies \:30 \times h = 585

 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \implies \: h =  \frac{585 }{30}

 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \implies \: 19.5cm

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Step-by-step explanation:

⠀\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}\\\\

⠀⠀\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\: Area:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}

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Answered by AbhinavRocks10
11

✯Answer:✯

➪19.5 cm

Step-by-step explanation:

  • ➪Given, Area of trapezium=585 cm^2

⟹ Parallel sides= 22cm and 38cm

  • Area of trapezium= 585

\sf\frac{1}{2}(a + b) \times h = 585

\sf\frac{1}{2} (22 + 38) \times h = 585

\sf\frac{60}{2} \times h = 585

⟹ 30h=585

⟹ h=585/30

⟹ h=19.5 cm

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