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A particle moves in a circle of radius 30 cm. Its linear
speed is given by v = 2t, where t is in second and vin
m/s. Its tangential and centripetal accelerations at t =
3 s are respectively
a)50 m/s2, 220 m/s2
b)100 m/s2,5 m/s2
c)120 m/s2, 2 m/s2
d)2 m/s2, 120 m/s2​

Answer 1

Answer:

Tang acc.=2m/s2

centri acc.=120m/s2

hence d option is correct

Explanation:

$a \: tangential = dv \div dt \\ \\ so \: simply \: diffrentiate \\ \\ a \: centripital = v {}^{2} \div r \\ \\ we \: will \: put \: r \: in \: metere \: so \: \\ \\ at \: 3 \: sec \\ v = 3 \times 2 \\ v = 6m \div s \\ now \\ 6 \times 6 \div 30 \times 10 { }^{ - 2} \\ \\ solving \\ a = 120m \div s {}^{2 }$

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