Chemistry, asked by gone69, 2 months ago

burning of sulphur's balanced equation​

Answers

Answered by Knockit
1

Answer:

S + O2 → SO2, ΔH = −297 kJ/mol.

Answered by vkvyas80
1

The burning of sulphur occurs as follows:-

S+O2⟶SO2

1 mole of sulphur reacts with 1 mole of O2 to form 1 mole of sulphur dioxide as per stoichiometry.

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