burning of sulphur's balanced equation
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Answer:
S + O2 → SO2, ΔH = −297 kJ/mol.
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The burning of sulphur occurs as follows:-
S+O2⟶SO2
1 mole of sulphur reacts with 1 mole of O2 to form 1 mole of sulphur dioxide as per stoichiometry.
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