Question

Bus A and Bus B leave the bus depot at 2 pm.
Bus A takes 15 minutes to do its route and bus B takes 25 minutes to complete its route.
At what time are they both back at the bus depot together?
Give your answer as a 12-hour clock time.

Answer 1

Answer:

3:15 pm

Step-by-step explanation:

you need to find the lowest common multiple of 15 and 25 which is 75

75 minutes = 60 mins + 15 mins = 1 hour and 15 minutes

2 pm + 1 hour and 15 mins = 3:15 pm

Answer 2

The time Bus A and Bus B  both back at the bus depot together is 3:15 pm.

Step-by-step explanation:

Given:

Bus A and Bus B leave the bus depot at 2 pm.

Bus A takes 15 minutes to do its route. Bus B takes 25 minutes to complete its route.

To Find:

The time Bus A and Bus B  both back at the bus depot together.

Solution:

As given,Bus A takes 15 minutes to do its route. Bus B takes 25 minutes to complete its route.

Bus A takes time = 15 minutes.

Bus B takes time = 25 minutes.

LCM of 15 and 25.

By the Prime Factorisation method

$15=3\times5\\25=5\times 5\\LCM (15, 25)=3\times5\times5=75$

LCM of 15 and 25  is  75 minutes.

As given,Bus A and Bus B leave the bus depot at 2 pm.

The time Bus A and Bus B  both back at the bus depot together

$= 2:00\ pm+ 75 \ min = 3:15\ pm.$

Thus,the time Bus A and Bus B  both back at the bus depot together is 3:15 pm.

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