Question

Bus accelerates uniformly from 54km/h to 72km/hr in 10 sec. Calculate

a) acceleratiom in m/s2

b) distance travelled by bus during its interval

Answer 1

u=54km/h=15m/s
v=72km/h=20m/s
a=acceleration
v=u+a.t

20=15+a.10
5=a.10
a=0.5m/s^2
distance traveled by bus,d=u.t+
0.5a.t^2
d=15*10+0.5*0.5*10*10
d=150+25
d=175 m

Answer 2

we will find acceleration and distance by using 3 equations of Motion