Question

Bus cross 19 poles in 10 sec and distance between two poles is 5 meter then what is spped of bus

Answer 1

Answer:

9m/sec

Step-by-step explanation:

total distance covered =(total number of poles -1)x(distance between two adjacent poles)

so distance covered=18x5=90m

time taken=10sec

so speed=90/10=9m/sec

Answer 2

Given,

A bus crosses 19 poles in 10 seconds.

The distance between the two poles is 5 meters.

To Find,

The speed of the bus.

Solution,

The formula for calculating the speed of an object is

Speed of object = Distance traveled/Time taken

In this question

The distance traveled by bus will be 18*5 = 90 meters.

Time taken by the bus = 10 seconds

So,

Speed of the bus = 90/10 = 9 m/sec

Hence, the speed of the bus is 9 m/sec.