Question

bus moving with a velocity of 12 m/s please stop the bus by applying brakes to provide a uniform declaration of
of 2m /S2 calculate the distance travelled by bus before ​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 12 m/s

Final velocity, v = 0 (As brakes applied)

Acceleration, a = 2 m/s²

To Find,

Distance covered s = ?

According to the 3rd equation of motion,

We know that

v² - u² = 2as

So, putting all the values, we get

v² - u² = 2as

⇒ 0² - (12)² = 2 × 2 × s

⇒ 144 = 4s

⇒ 144/4 = s

⇒ s = 36 m

Hence, the distance covered by bus is 36 m.

Answer 2

Explanation:

$\huge\bold\red{Answer:}$

To find:

calculate the distance travelled by bus before

Given:

velocity (u) =12ms^-1

acceleration (a) =2ms^-2

Formula used:

v²-u²=2as

values apply in formula

v²-u²=2as

0²-(12)²=2*2*s

4s=144

s=144/4

s=36 m

Distance travelled by the bus is 36 m.