Bus moving with a velocity of 60km/h is brought to rest in 20 sec by applying breakes find the acceleration
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Hey.
Here is the answer.
u = 60kmph = 60×5/18m/s = 50/3 m/s
v = 0 m/s. as stops after breaking
t = 20 s
As, v = u + a t
0 = 50/3 + a × 20
or, a = - 50/3×20
= -5/6 m/s^2
= -0.833 m/s^2
Thanks .
Here is the answer.
u = 60kmph = 60×5/18m/s = 50/3 m/s
v = 0 m/s. as stops after breaking
t = 20 s
As, v = u + a t
0 = 50/3 + a × 20
or, a = - 50/3×20
= -5/6 m/s^2
= -0.833 m/s^2
Thanks .
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