Question

bus of mass 2500 kg has a momentum of 1250 kg m/second. Calculate the velocity of bus.

Answer 1

Given :

• Mass of bus = 2500 kg
• Momentum = 1250 kg m/s

To find :

• Velocity of bus

According to the question,

$\star \boxed{\sf \red{Momentum(p)= Mass(m) \times Velocity(v)}}$

$\implies \sf{Velocity = \dfrac{Momentum}{Mass} }$

$\implies\sf{v= \dfrac{1250}{2500} } }$

$\sf \implies{v = 0.5 \: m {s}^{ - 1} } \green \bigstar$

So,the velocity of the bus is 0.5 m/s...

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

Formula for Force :

$\sf \purple{F = ma}$

• F stands for Force
• a stands for Acceleration
• m stands for Mass

__________....

• SI unit of momentum is kg m/s.
• SI unit of Force is Newton.
• SI unit of mass is kg
• SI unit of velocity is m/s

Answer 2

${\huge{\star{\underbrace{\tt{\red{Answer}}}}}}{\huge{\star}}$

Given :

• Mass = 2500 kg
• Momentum = 1250 kg m / second

To find :

• Velocity of bus.

Solution :

We know that,

${\boxed{\pink{\sf \ ✿ \ Momentum(p) \ = \ Mass(m) \times Velocity (v)}}}$

${\sf{➣ \ 1250 \ = \ 2500 \times v}}$

${\sf{➣ \ \frac{\cancel{1250}}{\cancel{2500}} \ = \ v}}$

${\sf{➣ \ v \ = \ 0.5 \ m/sec}}$

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