Question

bus started from A to B then after covering two third distance some fault occurs. Driver mentioned the fault quickly and bus will move again. But now the speed of the bus is reduced by one third and for this reason bus reaches at B. late by 1 hour what was the actual time in going B from A.​

Answer 1

6366473 is the answer

Step-by-step explanation:

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Answer 2

Answer:

6 hrs

Step-by-step explanation:

Let the actutal time be T taken by the bus to cover the distance with original speed.

Let the new time be T' taken by the bus to cover the same with the original and reduced speed.

Let D be the total distance travelled by the bus. So, the distance travelled by reduced speed will be 2/3D

Let S be the original speed. So, the reduced speed will be S - 1/3S = 2/3S

According to question, the bus arrived 1 hr late from the scheduled time of arrival.

This implies T'-T = 1

⇒ 2/3D  + 1/3D  _    D      =    1       (since distance/speed=time)

      S         2/3S        S

After solving the above equation and putting T in the place of D/S, we get T = 6 hrs. (Answer)