bus starts from rest and moving with a velocity of 72 kilometre per hour in 20 minutes calculate the acceleration and force if the mass of bus is 2000 kg
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0
Given,
Mass of car, M=2000kg
Velocity, V=72×
18
5
=20ms
−1
Apply kinematic equation of motion
v
2
−u
2
=2as
0−20
2
=2a×20
a=−10ms
−2
Breaking force, F=ma=2000×10=20 kN
Apply first kinematic equation
v=u+at
t=
a
v−u
=
−10
0−20
=2 sec
Breaking force is 20 kNand time is 2sec.
Answered by
0
Answer:
Given,
Initial Velocity (u) = 0 m/s
Final Velocity (v) = 72 km/hr
= (72*5/18) m/s
= 20 m/s
Time (t) = 20 mins
= (20*60) seconds
= 1200 seconds
v = u+at
= 20 = 0+(1200a)
= 20 = 1200a
= 0.01666 m/s²
Force = Mass*Acceleration
Given that Mass is 2000 kg,
= Force = 2000*0.01666
= Force = 33.32 N
I hope this helps.
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