Bus travels at a certain average speed fir a distance of 90km at an average speed of 10km/h more than the first speed.If it takes 3 hours to complete the jouney, what is its first speed
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Let the first speed of the bus be x.
As, speed,s=distance,d/time,t
So,t=d/s
But d is divided into two parts of 75km at speed x and 90km at speed(x+10)
So, t=75/(x) +90/(x+10)=3
By solving this we will get two values of x. x=50,-5
But the speed cann't be negative so the correct answer is 50km/h
As, speed,s=distance,d/time,t
So,t=d/s
But d is divided into two parts of 75km at speed x and 90km at speed(x+10)
So, t=75/(x) +90/(x+10)=3
By solving this we will get two values of x. x=50,-5
But the speed cann't be negative so the correct answer is 50km/h
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