Question

bus travels the first 30km with uniform speed of 30 km/hr and next 30km with uniform speed of 30km/h. Calculate the average speed of bus *​

Answer 1

Answer:

Avg speed of entire trip - V and total distance d=60Km and total time taken is t.

Avg speed in first 30Km _ v1=30Kmh-1 and time taken to cover it is t1.

Avg speed in last 30Km _ v2=? and time taken to cover it is t2.

V = d/t

V = 60/(t1+t2)

V = 60/[(30/v1)+(30/v2)]

40 = 60/[(30/30)+(30/v2)]

(30/30)+(30/v2) = 60/40 = 1.5

1 + (30/v2) = 1.5

30/v2 =0.5

v2 = 30/0.5

v2 = 60 Kmh-1

hope it's helpful u

Answer 2

Answer:

average speed = total distance covered/total time taken

total distance = 30+30 =60

time of first bus = d/s = 30/30=1hr

time taken by 2nd bus = 30/30 =1hr

total time taken= 2hrs

average speed of bus = 60/2 = 30 km/h

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