Physics, asked by sguttal2005, 1 day ago

Buses ply from city A to city B at regular interval of 15 minutes. Every bus from A to B moves with constan speed 40 km/h. A car X moving from city B to city A meets buses at an interval of 5 minutes. The speed the car X is n × 10 km/h. Find the value of n.​

Answers

Answered by mishrarishiraj219
23

Explanation:

Given:- Buses ply from city A to city B at regular interval of 15 minutes.

Every bus from A to B moves with constan speed 40 km/h.

let the moving car from city B to city A = x,

A meets buses at an interval of 5 minutes.

The speed the car X is n × 10 km/h

Speed = Distance / time,

The speed the car X = 10 km/h,

Distance = speed × time,

Distance = 40 × 15,

Distance = 600km.

the distance between City a to city b is equal to 600 km.

= n × 10 = 600

n = 600/10

n = 60 Ans.

Answered by hellaok024
7

Answer:

8

Explanation:

See, The distance between each bus is constant because it is given that time between each bus is constant.

Distance travelled in 15 minutes by bus = 40/4 = 10 KM

Speed of car = 10n Km/h

Speed of Bus = 40 Km/h

Imagine the buses are still.

Take relative Speed of car = 10n+40 Km/h

Time between meeting each bus = 1/12 hour

Distance between each bus = 10 Km/h

Distance / Speed = Time

10/10n+40 = 1/12

10n + 40 = 120

10 n = 80

n = 8

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