Question

Buses start from a terminal with speed 20kmph at intervals of 10 minute. What is the speed of a man coming from opposite direction towards the terminal if he meets buses at an interval of 8 minutes?

Answer 1

Hi friend,


Let the speed of the man be
x
x km/hr

Speed is inversely proportional to the time (when distance is constant).
Here the distance between the buses remains constant.

20 kmph is inversely proportional to 10 minutes
(20+x) kmph is inversely proportional to 8 minutes

⇒
20
×
10
=
(
20
+
x
)
×
8
200
=
160
+
8
x
40
=
8
x
x
=
5
⇒20×10=(20+x)×8200=160+8x40=8xx=5

speed of the man = 5 kmph


Hope this helps you
....

Please mark it as brainliest answer...☺☺☺