Question

but how log 3 base 9 = 1/16......

Answer 1

answer will be -7/8..

Answer 2

$( log_{9}( \sqrt{3 \sqrt{3 \sqrt{3} } } ) ) \times log_{10}(0.01) \\ = log_{9}( \sqrt{3 \sqrt{3 \times {3}^{ 0.5} } } ) \times log_{10}( {10}^{ - 2} ) \\ = log_{9}( \sqrt{3 \times {3}^{0.75} } ) \times log_{10}( {10}^{ - 2} ) \\ = log_{9}( { {3}^{ \frac{1.75}{2} })} \times - 2 \\ = log_{9}( {9}^{ \frac{1.75}{4} } ) \times - 2 \\ = \frac{1.75}{4} \times - 2 \\ = - \frac{1.75}{2 } \times \frac{4}{4} = - \frac{7}{8}$
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