Question

Butane, C4H1o, burns with the oxygen in air to give carbon dioxide and water
What is the amount (in moles) of carbon dioxide produced from 0.15 mole C4H10 ?
C4H10(g) + O2(g) - CO2(g) + H2O(g) (not balanced)
(A) 0.0375
(B) 0.15
(C) 0.6
(D) None
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Answer 1

Answer

(c) is the right answer 0.6

Answer 2

Answer:

0.6 moles of carbon dioxide are produced from 0.15 moles of butane.i.e.option(C).

Explanation:

The reaction of butane with oxygen in the air to give carbon dioxide and water is,

C₄H₁₀(g)+O₂(g)⇒ CO₂(g)+H₂O(g)             (1)

Where,

C₄H₁₀=butane

O₂=oxygen

CO₂=carbon dioxide

H₂O=water

After balancing equation (1) can be written as,

2C₄H₁₀(g)+13O₂(g)⇒ 8CO₂(g)+10H₂O(g)           (2)

From equation (2) we can see that 2 moles of butane produce 8 moles of carbon dioxide. So, 4 moles of carbon dioxide are produced from one mole of butane. Then 0.15 mole of butane will produce,

$0.15\times 4=0.6$ moles of carbon dioxide.

Hence,0.6 moles of carbon dioxide are produced from 0.15 moles of butane.i.e.option(C).

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