butyric acid contains carbon hydrogen and oxygen elements 4.24mg sample of butyric acid is completely burnt in oxygen it is 8.45mg co2 and 3.46 of water . what is the mean of each element determine emperical and molecular formula of butaric acid molecular mass in 88 unit.
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In CO2 the no of C atom is 1.
it means 44 mg of CO2 = 12 mg C
and 8.45 mg = 12 X 8.45 / 44
=2.30mg
% of C = 2.30 X 100 / 4.24
= 54.3 %
Similarly in H2O = 2H
in 3.46mg of H2O H = 2 X 3.46 /18
= 0.384mg
% of H = 0.348 x100 / 4.24 =9 %
% of O = 100 - 63.3
= 36.7%
By calculation we get the simple whole no ratio = 2:4:1
so empirical formula is C2H4O
and the value of n= 88 /44 =2
so molecular formula = c4 H8 O2
it means 44 mg of CO2 = 12 mg C
and 8.45 mg = 12 X 8.45 / 44
=2.30mg
% of C = 2.30 X 100 / 4.24
= 54.3 %
Similarly in H2O = 2H
in 3.46mg of H2O H = 2 X 3.46 /18
= 0.384mg
% of H = 0.348 x100 / 4.24 =9 %
% of O = 100 - 63.3
= 36.7%
By calculation we get the simple whole no ratio = 2:4:1
so empirical formula is C2H4O
and the value of n= 88 /44 =2
so molecular formula = c4 H8 O2
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