Buy An abject covers 2/5 of total distance with a speed of
v1 and remaining distance with a speed of
v2 then find the avearage speed of this.
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Explanation:
V1 = (2/5 D)/t1
V2 = (3/5D)/t2
V = D/T
= D/ (t1 +t2)
=D/ (2D/5V1 + 3D/5V2)
= 1 / (2/5V1 + 3/5V2)
= 5 / ( 2/V1+ 3/V2)
= 5 V1 V2 /( 2V2 +3V1)
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