bx2+x+5 & bx3-2x+5are divided by x-3 , then m&n are remainder resp If m-n=0 then find value of b ?
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Answer:
bx3-2x3+5=n
27b-1=0
9b+8-(27b-1)=0
9b-27b+8+1=0
-18b+9=0
b=1\2
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