Question

bx²- x [a² +b^] + a²b=0.​

Answer 1

Answer:

$bx ^{2} - b^{2} x - a^{2} x + a^{2}b = 0$

bx(x-b)-a²(x-b)=0

(bx-a²) (x-b)=0

x=a²/b,

x=b

answer