Question

by
34. A rigid insulated box is divided into two
.
1 gm mole of ideal gas at temperature
T, and the other by 2gm moles of the same
ideal gas at temperature Tg. When the
partition is removed, what is the final
equilibrium temperature of the mixture?​

Answer 1

Answer:

t1 + 2t2.

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3

Explanation:

hope so it wil help you

Answer 2

Answer:

$(T1+2T2)/3$

Explanation:

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume V1 and contains ideal gas at pressure P1 and temperature T1

​The other chamber has volume V2 and contains the same ideal gas at pressure P2and temperature T2If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will be:    (T1+2T2)/3