Question

by ( a + b ) ² solve these questions . ( I don't know how to solve squared sums pls help )​

Answer 1

Answer:

All the answers are below.

Step-by-step explanation:

$(1) {(3 \sqrt{2} + 5 \sqrt{3} )}^{2} \\ = 18 + 30 \sqrt{6} + 75 \\ = 93 + 30 \sqrt{6}$

$(2) {(2 \sqrt{3} - \sqrt{2} )}^{2} \\ = 12 - 4 \sqrt{6} + 2 \\ = 14 - 4 \sqrt{6}$

$(3) {(6 \sqrt{2})}^{2} - {(3 \sqrt{2})}^{2} \\ = (6 \sqrt{2} + 3 \sqrt{2})(6 \sqrt{2} - 3 \sqrt{2}) \\ = 9 \sqrt{2} \times 3 \sqrt{2} \\ = 27 \times 2 \\ = 54$

$(4)(5\sqrt{3}+2\sqrt{2})(\sqrt{2} +\sqrt{3})\\=5 \sqrt{6} + 15 + 4 + 2 \sqrt{6} \\ = 19 + 7 \sqrt{6}$

$(5)(3\sqrt{2}-2\sqrt{2})(\sqrt{3} +\sqrt{2})\\=3\sqrt{6}+6-2\sqrt{6}-4 \\ = 2 - \sqrt{6}$

$(6)(2 \sqrt{2} + 3 \sqrt{2})( \sqrt{2} + \sqrt{3} - \sqrt{5}) \\ = 4 + 2 \sqrt{6} - 2 \sqrt{10} + 6 + 3 \sqrt{6} - 3 \sqrt{10} \\ = 10 + 5 \sqrt{6} - 5 \sqrt{10}$

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