By actual division, find if
(i) x - 4 is a factor of x2 - 5x - 15
Answers
Answered by
0
Answer:
No, (x-4) is not a factor of (x^2 - 5x -15).
Step-by-step Explanation:
please find the attached solution.
For (x-4) to be a factor of (x^2 - 5x -15), remainder should be zero.
after actual division, we get a remainder of -19.
Hence, it is not a factor.
Attachments:
![](https://hi-static.z-dn.net/files/d5f/8485c4eb5971ef8e8dc1cd70ea863226.jpg)
Answered by
0
Answer:
x-4)x^2-5x-15(x-1
x^2-4x
________
-x-15
-x+4
________
-19
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