Question

by actual division method find quotient and remainder
when,
2x^4-6x^3+2x^2-x+2 divided by x+2​

Answer 1

Step-by-step explanation:

heres ur ans...hope it helps

Answer 2

Answer:

92 will be the remainder for the given equation. So, 92 is the answer to your problem

Step-by-step explanation:

Soln: We have various methods to solve this problem like common division, remainder theorem, factor theorem, synthetic division. But, very easy methods in these are synthetic division, remainder theorem and factor theorem that according to me. So, now I'll explain in the remainder theorem.

So, let x+2=0.

=> x = 0–2

x = -2

Therefore, we get the value of 'x's, that is -2. So, now substitute the -2 in the given equation.

f(x) = 2x⁴-6x³+2x²-x+2

=> f(-2) = 2(-2)⁴-6(-2)³+2(-2)²-(-2)+2

f(-2) = 2(16)-6(-8)+2(4)+2+2

f(-2) = 32+48+8+2+2

f(-2) = 92

Therefore, 92 will be the remainder for the given equation. So, 92 is the answer to your problem.

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