by aljebraic identities
multiply
a) (2a+3)(2a+5)
b) (3p-4q)(3p-4q)
Answers
Answered by
5
A. (2a+3)(2a+5)
= (2a)² + 3*5 + 2a(3+5)
=4a² + 15 + 16a
B. (3p-4q)(3p+4q)
= (3p)² - (4q)²
= 9p² - 16q²
= (2a)² + 3*5 + 2a(3+5)
=4a² + 15 + 16a
B. (3p-4q)(3p+4q)
= (3p)² - (4q)²
= 9p² - 16q²
rajlaxmidash201:
excuse me! ur second answer is wrong. u had copied the question incorrectly. please correct it
what is the aljebraic identity
Answered by
6
1) (2a+3)(2a+5)
=2a(2a+5)+3(2a+5)
=4a²+10a+6a+15
=4a²+16a+15
2) (3p-4q)(3p-4q)
=3p(3p-4q)-4q(3p-4q)
=9p²-12pq-12pq+16q²
=9p²-24pq+16q²
=2a(2a+5)+3(2a+5)
=4a²+10a+6a+15
=4a²+16a+15
2) (3p-4q)(3p-4q)
=3p(3p-4q)-4q(3p-4q)
=9p²-12pq-12pq+16q²
=9p²-24pq+16q²
what is the aljebraic identity
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