Question

by any of the numbers 35, 56 and 91
leaves remainder 7 every time.
Find the smallest number which when divided​

Answer 1

Answer:

3647

Step-by-step explanation:

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

Answer 2

Answer:

3647

Step-by-step explanation:

first we need to take the l.c.m of 35 , 56, 91 we get the l.c.m 3640 and then we add 7 . 3640+7=3647