By applying laws of logarithm express log m - log n +1/2 log p as a single logarithm term
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6
hai friend,
here is your answer
log m-log n+1/2log p
=logm/n+logp^1/2
=log (m/n*√p )
=log(m√p/n)
hope helped
here is your answer
log m-log n+1/2log p
=logm/n+logp^1/2
=log (m/n*√p )
=log(m√p/n)
hope helped
Answered by
3
log m - log n +1/2 log p
= log (m/n) + log √p [ ∵ log a - log b = log (a/b) ; n log a = log a^n]
= log (m √p)/n [ ∵ log a + log b = log (ab) ]
= log (m/n) + log √p [ ∵ log a - log b = log (a/b) ; n log a = log a^n]
= log (m √p)/n [ ∵ log a + log b = log (ab) ]
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