By applying substitution and elimination ways, find solution of the following linear equations:
3x + y = 7
5x - 3y = 7
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3x + y = 7 ...(1)
5x - 3y = 7 ...(2)
By Elimination Method
Multiplying eqn.(1) by 3
9x + 3y = 21 ...(3)
Adding eqn (2) and (3)
14x = 28
x = 2.
Substituting value if x in eqn (1)
3(2) + y = 7
6 + y = 7
y = 1.
By Substitution Method
Considering eqn (1),
3x + y = 7
or, y = 7 - 3x...(4)
Substituting (4) in eqn (2)
5x - 3(7-3x) = 7
5x -21 + 9x = 7
14x = 28
x = 2.
Substituting value of x in eqn (4)
y = 7-3(2)
or, y = 7-6
or, y = 1.
Finally, we get x=2 and y=1.
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