By applying the brakes without causing the skid the driver of a car is able to stop his car within a distance of 5 metre if it is going at 36 kmph, if the car were going at 72 kmph using the same brakes he can stop the car over a distance of
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Answered by
11
hey !! bro the answer is 10m
<explanation---
since ,in 36kmph car stopped at a distance of 5m
therefore In 1 kmph car stopped at a distance of 5/36 m
and then ln 72 kmph using the same brakes the car stopped at a distance of 5/36*72= 10 m
I hope u understand...
<explanation---
since ,in 36kmph car stopped at a distance of 5m
therefore In 1 kmph car stopped at a distance of 5/36 m
and then ln 72 kmph using the same brakes the car stopped at a distance of 5/36*72= 10 m
I hope u understand...
Answered by
4
We know that ,
W=change in K.E
change in K.E1/change in K.E2
=W1/W2=FS1 /FS2
I.e 36/72 =5/S2
I.e 1/2 =5/S2
Therefore,S2 = 10
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