Math, asked by sweetysiri92, 1 year ago

by checking only  the equation and the coefficients, determine the smallest and largest possible rational roots of the equation
2x^4+x^2+22x+6=0 and
2x^4+x^2-22x+8=0

Answers

Answered by kvnmurty
0
2 x^4 + x² + 22 x + 6 = 0    divide expression by 2 to get
x^4 + 0.5 x² + 11 x + 3 = 0

Possible values of rational roots /zeros :  + 3  or -3  or + 1 or - 1
         =   factors of constant term

   2x^4 + x^2  - 22 x  + 8 = 0        divide by 2
       x^4 + 0.5 x^2 - 11 x + 4 = 0
         possible of  zeros (rational values) :  +1  -1  +2  -2  +4  -4



kvnmurty: i solved these problems earlier in the evening already. why raise another question again ? sweety?
sweetysiri92: Thankyou
Similar questions