Question

By completing square method
${x }^{2} - 4x - 1 = 0$
Please answer this question ​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ {x}^{2} - 4x - 1 = 0 \\ \\ {( \frac{1}{2} \times coeff \: of \: x)}^{2} \\ {( \frac{1}{2} \times ( - 4)) }^{2} \\ 4 \\ {x}^{2} - 4x + 4 - 4 - 1 = 0 \\ {(x - 4)}^{2} = 5 \\ x - 4 = + / - 5 \\ x = - 1 \: \: \: \: \: or \: \: \: \: \: \: \: x = 9$

Answer 2

Answer:

x 2 −4x−1=0

( 21×coeffofx)

2( 21 ×(−4))

24x 2−4x+4−4−1=0

(x−4)

2=5

x−4=+/−5

x=−1orx=9