By completing the square express the inequality r? +8x+c >0 in the form fx+al > b where a and b are constants. Therefore, find the interval of x so that x² +8x +10 is always more than 3.
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Answer:
The given equation can be written as
x
2
−8x+a
2
−6a=0
Since the roots of the above equation are real,
∴B
2
−4AC≥0⇒64−4(a
2
−6a)≥0
⇒a
2
−6a−16≤0
⇒(a+2)(a−8)≤0
⇒a ϵ [−2,8]
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