By considering 3^1 3^2,3^3 3^4,3^5 .. and looking for a pattern, find the last digit of 33
Answers
Answered by
0
Answer:
hello, it is arithmetic progression you can use that formula
Step-by-step explanation:
like....
a=3^1
d= a2 _a1
so... 3^2-3^1
.=3^1
N=33
an=a+(n-1)d
3^1+(33-1)3^1
=3+((32)3
=. =3+96
99
99 is answer... ok
Answered by
0
Answer:
Step-by-step explanation:
I don’t know since I am doing this to earn points
Similar questions