Question

by cross multiplication method,find such two digit number such that, the digit at unit's place is twice the digit at tens place and the number obtained by interchanging the digits of the number is 36 more than the original number​

Answer 1

Step-by-step explanation:

Let the number be xy, where y is at unit's place and x is at ten's place.

2x = y

2x-y = 0

Interchange the digits = yx

new number = 10y+x

original number = 10x+y

(10x+y) + 36 = 10y+x

9x-9y+36 = 0

x - y + 4 = 0

solving these two equations, you will get the values of x and y

x = 4, y = 8

Thus the number is 48

Answer 2

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