by decomposition of 50 grams CaCO3 the amount of CaO producad will be what
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Answer:
14g of CaO is produced
Explanation:
Mass of atoms of elements :
Ca =40u
C = 12u
O= 16u
CaCO3 = 40 +12+16(3) =100g = 1mole
Given 25g = 25/100 = 0.25 mole
CaCO3 ( on heating )---> CaO + CO2
CaO = 40 + 16 = 56g = 1 mole
For 0.25 moles CaO produced = 56×0.25 = 14g
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