Question

By dissolving 25.6g sulphur in 1000g napthalene depursions in freezing point was found to be 0.68k. Calculate molecular formula of sulphur.[ For napthalene Kr= 6.8k kg mol-1].

Answer 1

Answer:

∆Tf = kf ×m

0.68 = 6.8 × m

m = 0.1

n/1 = .1

25.6/M = 0.1

M = 246gram

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