Question

+by division method

p(x) x^3-6x^2+2x-4.
g(x) -3x+1​

Answer 1

Answer:when we divide f(X) by g(X)

g(X) = 3x-1

so root = 1/3

then by remainder theorem

f(1/3) = (1/3)^3-6*(1/3)^2+2*1/3-4

= 1/27-6/9+2/3-4

= 1/27-4

= 1-27*4/27

= -107/27

Step-by-step explanation: mark me brainliest plsssss