by elimination method, 2x-5y=4,&3x-2y=-16
Answers
By elimination method
2x-5y=4... (1)
3x-2y=-16... (2)
Multiply eqn(1)×3
3(2x-5y=4)
6x-15y=12...(3)
Multiply eqn(2)×2
2(3x-2y=-16)
6x-4y=-32... (4)
eqn(3)&(4)
6x-15y=12
6x-4y=-32
(-). (+) (+)
_______
- 11y=44
y=44/-11
y=4
Substitute y=4 in eqn(1)
2x-5y=4
2x-5(4)=4
2x-20=4
2x=4+20
2x=24
x=24/2
x=12
By elimination method:x=12, y=4
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Answer:
take
2x-5y=4-----------(1)
3x-2y= -16--------(2)
(1)×2-(2)×5
4x-10y= 8
15x-10y=-80
-. +. +
----------------------------
-11x=88
11x=-88
x=-88/11
x=-8
substitute x=-8in(1)
2x-5y=4
2(-8)-5y=4
-16-5y=4
-5y=4+16
-5y=20
5y=-20
y=-20/5
y=-4
therefore,
x=-8and y=-4
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