Question

by elimination method 3x-5y=4,9x=2y+7​

Answer 1

$\textbf{3x - 5y = 4} \: \\ \\ \textbf{9x = 2y + 7} \\ \rightarrow \text{9x - 2y = 7}$

• Now we have two equations

$\text{3x - 5y = 4} - - - - (1) \: \\ \text{9x - 2y = 7} - - - - (2)$

Eliminating x :

• Subtracting equation (2) from equation (1) × 3 , we get....

$\text{9x - 15y = 12} \\ \\ \text{9x - 2y \: = \: 7} \\ - \: \: \: \: + \: \: \: \: \: \: \: \: - \\ \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \text{0 \: - 13y \: = \: 5 }$

$\text{ \small{ \: \: \: \: - 13y = 5 }} \\ \rightarrow \: \boxed{ \text {\small{ \: y }} = - \frac { \small{5}}{ \small{13} } }</p><p>$

• Putting the value of y in equatio (1)

$\text{3x - 5y = 4} - - - - (1) \: \\ \\ \text {\small{ 3x - 5} \times - \frac{5}{13} } = 4 \\ \\ \text{ \small{3x + \frac{25}{1 3} = 4 }} \\ \\ \text{ \small{3x = 4 - \frac{25}{13} }} \\ \\ \text{ \small{3x = \frac{52 - 25}{13} }} \\ \\ \text{ \small{x = \frac{ \cancel{27}}{13} \times \frac{1}{ \cancel{ \: 3}} }} \\ \\ \rightarrow \: \: \boxed{ \text{ \small{x}} = \frac{\small{9}}{\small{13}} }$

Answer 2

Explanation:

x = 9/13

&

y = -5/13

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