By elimination method find values of u and v for given equations 8u+20v=1 and 9u + 18 v = 1
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u=1/18 & v=1/36
multiply first equation with 9 and and second equation with 8....after the multiplication eliminate equation 1 & equation 2
multiply first equation with 9 and and second equation with 8....after the multiplication eliminate equation 1 & equation 2
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Solution....
8u + 20v = 1
multiply by 9 on both sides.
So,
72u + 180v = 9 ....................eq1.
Now,
9u + 18v = 1
Multiply by 8 on both sides
72u + 144v = 8.....................eq.2
Now, subtracting eq 2 from eq.1
72u + 180v = 9
-72u - 144v = -8 [ by change the sign]
____________
36v = 1
v = 1/36__
put value of v in eq.2
72u + 144 × 1/36 = 8
72u + 4 = 8
72u = 8-4 = 4
u = 4/72
u = 18._____
Hope this will help you.....
☞ ⛧⛧Mr. Thakur ⛧⛧
8u + 20v = 1
multiply by 9 on both sides.
So,
72u + 180v = 9 ....................eq1.
Now,
9u + 18v = 1
Multiply by 8 on both sides
72u + 144v = 8.....................eq.2
Now, subtracting eq 2 from eq.1
72u + 180v = 9
-72u - 144v = -8 [ by change the sign]
____________
36v = 1
v = 1/36__
put value of v in eq.2
72u + 144 × 1/36 = 8
72u + 4 = 8
72u = 8-4 = 4
u = 4/72
u = 18._____
Hope this will help you.....
☞ ⛧⛧Mr. Thakur ⛧⛧
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