Question

By elimination method solve 7x+3y-8=0 3x-4y-14=0​

Answer 1

Answer:

x=2 y=-2

Step-by-step explanation:

7x+3y-8=0

Multiply the above equation by 4 times which gives the below equation

28x+12y-32=0

3x-4y-14=0 Multiply this equation by 3 times which gives

9x-12y-42=0

Now add both equations which gives

37x=74

x=2

Now substitute this in any equation

7(2)+3y=8

3y=8-14

3y=-6

y=-2

Hope it helps

Answer 2

Answer:

◘ 7x + 3y - 8 = 0, 3x - 4y - 14 = 0 by elimination method.

7x + 3y - 8 = 0

7x + 3y = 8 . . . . (1)

3x - 4y - 14 = 0

3x - 4y = 14 . . . . (2)

✯ Multiply equation (1) by 3 and (2) by 7, we get

21x + 9y = 24 . . . . (3)

21x - 28y = 98 . . . . (4)

❖ Adding (3) and (4) we get,

21x + 9y = 24

21x - 28y = 98

(-) (+) (-)

______________

37y = - 74

y = - 74/37

y = - 2

❃ Substituting the value of y = - 2 in equation (1) we get,

★ 7x + 3y = 8

➭ 7x + 3(- 2) = 8

➭ 7x - 6 = 8

➭ 7x = 8 + 6

➭ 7x = 14

➭ x = 14/7

➭ x = 2

∴ The value of x = 2, y = - 2 is the solution of the system of the given equations.