Math, asked by bindibinsa, 8 months ago

by Euclid's division algorithm find 305,793

Answers

Answered by rk4846336
1

Answer:

Since 793>305, we apply the division lemma to 793 and 305 to obtain:

793=305×2+183

Since remainder 183

=0, we apply the division lemma to 305 and 183 to obtain:

305=183×1+122

We consider the new divisor 183 and new remainder 122, and apply the division lemma to obtain

183=122×1+61

Now, the new divisor is 122 and new remainder is 61, and apply the division lemma to obtain

122=61×2+0

Since the remainder is zero, the process stops.

Also, the divisor at this stage is 61,

Hence, the HCF of 793 and 305 is 61.

Answered by adityasrivastava6578
0

Answer:

Since 793>305, we apply the division lemma to 793 and 305 to obtain:

793=305×2+183

Since remainder 183  

​  

=0, we apply the division lemma to 305 and 183 to obtain:

305=183×1+122

We consider the new divisor 183 and new remainder 122, and apply the division lemma to obtain

183=122×1+61

Now, the new divisor is 122 and new remainder is 61, and apply the division lemma to obtain

122=61×2+0

Since the remainder is zero, the process stops.

Also, the divisor at this stage is 61,

Hence, the HCF of 793 and 305 is 61.

Step-by-step explanation:

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