by factorisation method
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Step-by-step explanation:
x² - 2ax - (4b² - a²) = 0
=> x² - 2ax - ( 2b + a)(2b - a) = 0
=> x² - (2b + a)x - (2b - a)x - (2b + a)(2b - a) = 0
=> x ( x - (2b + a)) - (2b - a)(x - ( 2b + a)) = 0
=> (x - (2b + a))(x -(2b - a)) = 0
Either | or
x - (2b + a) = 0 | x - ( 2b - a) = 0
=> x = 2b + a | => x = 2b - a
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