Question

by factorisation method or Quadratic equation method​

Answer 1

Answer:

1)18x²-3x-6=0

6x²-x-2=0

6x²-4x+3x-2=0

(6x²-4x)+(3x-2)=0

2x(3x-2)+1(3x-2)=0

(3x-2)(2x+1)=0

2)x(2x-1)=3

2x²-x=3

2x²-x-3=0

2x²-3x+2x-3=0

(2x²-3x)+(2x-3)=0

x(2x-3)+1(2x-3)=0

(2x-3)(x+1)=0

3)(x+3)(x-5)=(-7)

x(x-5)+3(x-5)=(-7)

x²-5x+3x-15+7=0

x²-2x-8=0

x²-4x+2x-8=0

x(x-4)+2(x-4)=0

(x-4)(x+2)=0