By factorize the binomial(a2b2-y4) is
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Answer:
– b)
Sol:
Given:[latex]x^{4} – y^{4} [/latex]
=[latex]x^{4} – y^{4} = (x^{2})^{2} – (y^{2}) ^{2}[/latex]
The given identity is
= [latex]a^{2} – b^{2} = (a + b) (a – b) [/latex]
=[latex] (x^{2})^{2} – (y^{2})^{2} = (x^{2} + y^{2}) (x^{2} – y^{2})[/latex]
= [latex](x^{4}) – (y^{4}) = (x^{2} + y^{2}) (x^{2} – y^{2})[/latex]
Here we have
[latex]x^{2} – y^{2} = (x + y) (x – y)[/latex]
Therefore, [latex]x^{4} – y^{4} = (x^{2} + y^{2}) (x + y) (x – y)[/latex
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