Question

by gauss jordon method solution of x+y=2,2x+3y=5 is​

Answer 1

Answer:

Explanation:

We can write the system of linear equation in matrix vector form

A

x

−

=

b

−

(

2

−

3

3

4

)

(

x

y

)

=

(

5

−

1

)

So the Augmented Matrix is:

(

2

−

3

∣

5

3

4

∣

−

1

)

We can now perform elementary row operations:

(

2

−

3

∣

5

3

4

∣

−

1

)

1

2

R

1

→

R

1

−−−−−→

(

1

−

3

2

∣

5

2

3

4

∣

−

1

)

(

1

−

3

2

∣

5

2

3

4

∣

−

1

)

R

2

−

3

R

1

→

R

2

−−−−−−−−→

(

1

−

3

2

∣

5

2

0

17

2

∣

−

17

2

)

And so:

17

2

y

=

−

17

2

⇒

y

=

−

1

Back substituting into R1:

x

−

3

y

2

=

5

2

⇒

x

+

3

2

=

5

2

⇒

x

=

1